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6x^2-3.375=0
a = 6; b = 0; c = -3.375;
Δ = b2-4ac
Δ = 02-4·6·(-3.375)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-9}{2*6}=\frac{-9}{12} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+9}{2*6}=\frac{9}{12} =3/4 $
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